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After the excitation of PS I, the electrons are passed through ferredoxin to

(a) water, forming H₂O₂ Your answer
(b) PS II Your answer
(c) plastoquinone, back to PS II Your answer
(d) NADP reductase, which reduces NADP⁺ Correct

Your answer: Correct answer: (d)

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Explanation

Why (d) is correct

Electrons from excited PS I pass through ferredoxin to NADP reductase, which reduces NADP⁺ to NADPH + H⁺.

Why the other options are wrong

(a) · your answer Water is not the acceptor; H₂O₂ is not formed.
(b) · your answer Electrons do not return to PS II.
(c) · your answer In non-cyclic flow they do not return to plastoquinone and PS II.

NCERT point: Last step of the Z scheme: NADP⁺ + 2e⁻ + H⁺ → NADPH.

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