General
✓✗In the diazonium coupling reactions, the nitrogen atoms are
- retained in the product
- oxidised to NO2
- lost as N2
- reduced to NH3
General
✓✗The number of structural isomers of C3H9N is
- 4
- 5
- 2
- 3
General
✓✗In the coupling reaction of diazonium salts with aniline, the diazonium ion acts as
- a reducing agent
- a nucleophile
- a free radical
- an electrophile
General
✓✗Aniline \( \xrightarrow{\;\text{NaNO}_2\text{/HCl, 273 K}\;} \) A \( \xrightarrow{\;\text{H}_2\text{O, warm}\;} \) B. B is
- chlorobenzene
- benzene
- nitrobenzene
- phenol
General
✓✗Match List I (reactant and reagent) with List II (product).
Choose the correct answer from the options given below.
| List I | List II |
| P. Ethylamine + HNO2 (room temperature) | I. N-Nitrosamine |
| Q. Diethylamine + HNO2 | II. Ethanol + N2 |
| R. Aniline + HNO2 (273−278 K) | III. Phenol |
| S. Benzenediazonium chloride (warm water) | IV. Benzenediazonium chloride |
- P-III, Q-I, R-IV, S-II
- P-II, Q-I, R-IV, S-III
- P-I, Q-II, R-IV, S-III
- P-II, Q-IV, R-I, S-III
General
✓✗CH3OH \( \xrightarrow{\;\text{SOCl}_2\;} \) A \( \xrightarrow{\;\text{KCN, aq. EtOH}\;} \) B \( \xrightarrow{\;\text{Na(Hg), EtOH}\;} \) C \( \xrightarrow{\;\text{(i) NaNO}_2\text{ + HCl;\;(ii) H}_2\text{O}\;} \) D (major). D is
- CH3CH2OH
- CH3CHO
- CH3CH2Cl
- CH3CH2NH2
General
✓✗Benzoic acid can be obtained from aniline by
- Hofmann degradation
- diazotisation, CuCN, then acid hydrolysis
- bromination, then hydrolysis
- acetylation, then oxidation
General
✓✗Hofmann bromamide degradation converts an amide into
- a secondary amine
- a primary amine with one carbon atom less
- a primary amine with one carbon atom more
- a nitrile
General
✓✗The compound that does NOT undergo Friedel−Crafts alkylation but gives a positive carbylamine test is
- N-methylaniline
- pyridine
- triethylamine
- aniline
General
✓✗Direct nitration of aniline with conc. HNO3/H2SO4 is not used to make p-nitroaniline because
- it gives nitrobenzene
- it gives only o-nitroaniline
- aniline is partly oxidised to tarry products and the anilinium ion gives much m-nitroaniline
- aniline does not react with HNO3
General
✓✗Aniline \( \xrightarrow{\;\text{NaNO}_2\text{/HCl, 273 K}\;} \) A \( \xrightarrow{\;\text{KI}\;} \) B \( \xrightarrow{\;\text{Mg, ether;\;then CO}_2\text{;\;H}_3\text{O}^+\;} \) C. C is
- iodobenzene
- benzoic acid
- benzaldehyde
- phenol
General
✓✗Which of the following does NOT react with nitrous acid to give N2?
- Propylamine
- N,N-Dimethylaniline
- Ethylamine
- Methylamine
General
✓✗The amine that reacts with Hinsberg’s reagent to give an alkali-insoluble product is
- diisopropylamine, (CH3)2CH−NH−CH(CH3)2
- triethylamine
- 3-methylbutan-2-amine
- 2-methylpentan-2-amine
General
✓✗The method by which aniline CANNOT be prepared is
- degradation of benzamide with bromine in alkaline solution
- treating potassium phthalimide with chlorobenzene followed by hydrolysis with aqueous NaOH
- hydrolysis of phenyl isocyanide with acidic solution
- reduction of nitrobenzene with H2/Pd in ethanol
General
✓✗Statement I: Alkylamines are stronger bases than ammonia.
Statement II: Arylamines are stronger bases than ammonia.
Statement II: Arylamines are stronger bases than ammonia.
- Both Statement I and Statement II are correct
- Both Statement I and Statement II are incorrect
- Statement I is correct but Statement II is incorrect
- Statement I is incorrect but Statement II is correct