General
✓✗Specific volume of cylindrical virus particle is 6.02 ´ 10–2 cc/g whose radius and length are 7 Å and 10 Å respectively. If NA = 6.02 ´ 1023, find molecular weight of virus.
- 15.4 kg/mol
- 1.54 ´ 104 kg/mol
- 3.08 ´ 104 kg/mol
- 3.08 ´ 103 kg/mol
General
✓✗6.02 ´ 1020 molecules of urea are present in 100 mL of its solution. The concentration of solution is
- 0.001 M
- 0.1 M
- 0.02 M
- 0.01 M
General
✓✗The number of moles of oxygen in one litre of air containing 21% oxygen by volume, under standard conditions, is
- 0.0093 mol
- 2.10 mol
- 0.186 mol
- 0.21 mol
General
✓✗In the reaction,
4NH3(g) + 5O2(g) ® 4NO(g) + 6H2O(l)
when 1 mole of ammonia and 1 mole of O2 are made to react to completion :
4NH3(g) + 5O2(g) ® 4NO(g) + 6H2O(l)
when 1 mole of ammonia and 1 mole of O2 are made to react to completion :
- all the oxygen will be consumed
- 1.0 mole of NO will be produced
- 1.0 mole of H2O is produced
- all the ammonia will be consumed
General
✓✗1 cc N2O at NTP contains
-
atoms
-
molecules
-
electrons
- all of the above
General
✓✗0.24 g of a volatile gas, upon vaporisation, gives 45 mL vapour at NTP. What will be the vapour density of the substance? (Density of H2 = 0.089 g/L)
- 95.93
- 59.93
- 95.39
- 5.993
General
✓✗The number of gram molecules of oxygen in 6.02 ´ 1024 CO molecules is
- 10 g molecules
- 5 g molecules
- 1 g molecules
- 0.5 g molecules
General
✓✗How many moles of lead (II) chloride will be formed from a reaction between 6.5 g of PbO and 3.2 g HCl?
- 0.011
- 0.029
- 0.044
- 0.333
General
✓✗Which has the maximum number of molecules among the following?
- 44 g CO2
- 48 g O3
- 8 g H2
- 64 g SO2
General
✓✗A mixture of 2.3 g formic acid and 4.5 g oxalic acid is treated with cone. H2SO4. The evolved gaseous mixture is passed through KOH pellets. Weight (in g) of the remaining product at STP will be
- 1.4
- 3.0
- 2.8
- 4.4
General
✓✗Suppose the elements X and Y combine to form two compounds XY2 and X3Y2. When 0.1 mole of XY2 weighs 10 g and 0.05 mole of X3Y2 weighs 9 g, the atomic weights of X and Y are
- 40, 30
- 60, 40
- 20, 30
- 30, 20
General
✓✗If Avogadro number NA, is changed from 6.022 ´ 1023 mol–1 to 6.022 ´ 1020 mol–1, this would change
- the mass of one mole of carbon
- the ratio of chemical species to each other in a balanced equation
- the ratio of elements to each other in a compound
- the definition of mass in units of grams.
General
✓✗The number of water molecules is maximum in
- 1.8 gram of water
- 18 gram of water
- 18 moles of water
- 18 molecules of water.
General
✓✗The dimensions of pressure are the same as that of
- force per unit volume
- energy per unit volume
- force
- energy
General
✓✗Oxidation numbers of A, B, C are +2, +5 and –2 respectively. Possible formula of compound is
- A2(BC2)2
- A3(BC4)2
- A2(BC3)2
- A3(B2C)2