General
✓✗Methane cannot be prepared by the Wurtz reaction because
- the product always contains at least two carbon atoms
- methyl halides do not react with sodium
- methane is a gas
- sodium does not dissolve in ether
General
✓✗The major product A of the reaction CH3−CH(CH3)−CH=CH2 + HBr → A is
- CH3−C(Br)(CH3)−CH2CH3
- CH3−CH(Br)−CH(CH3)−CH3
- CH3−CH(CH3)−CH(Br)−CH3 only, via a primary cation
- CH3−CH(CH3)−CH2−CH2Br
General
✓✗Baeyer’s reagent test is used to detect
- aromatic rings only
- aldehydes
- carbon−carbon unsaturation
- alcohols
General
✓✗1 mol of a hydrocarbon on complete combustion gives 4 mol CO2 and 3 mol H2O. The hydrocarbon could be
- benzene
- butane
- but-1-ene
- but-1-yne or buta-1,3-diene (C4H6)
General
✓✗The general formula of alkynes is
- CnH2n
- CnHn
- CnH2n+2
- CnH2n−2
General
✓✗The side-chain chlorination of toluene with excess Cl2 in light finally gives
- hexachlorobenzene
- p-chlorotoluene
- o-chlorotoluene
- C6H5CCl3
General
✓✗An alkene A on hydroboration−oxidation gives 2-methylpropan-1-ol. On acid-catalysed hydration the same alkene gives
- butan-2-ol
- 2-methylpropan-1-ol
- butan-1-ol
- 2-methylpropan-2-ol
General
✓✗Benzene reacts with CH3COCl in the presence of anhydrous AlCl3. The product is converted to ethylbenzene by
- oxidation with KMnO4
- ozonolysis
- Clemmensen reduction (Zn−Hg/HCl)
- nitration
General
✓✗Statement I: The boiling points of the three isomeric pentanes follow the order n-pentane > isopentane > neopentane.
Statement II: When branching increases, the molecule becomes more spherical. This gives a smaller surface area of contact, so the intermolecular forces between the spherical molecules are weaker, lowering the boiling point.
Statement II: When branching increases, the molecule becomes more spherical. This gives a smaller surface area of contact, so the intermolecular forces between the spherical molecules are weaker, lowering the boiling point.
- Both Statement I and Statement II are correct
- Both Statement I and Statement II are incorrect
- Statement I is correct but Statement II is incorrect
- Statement I is incorrect but Statement II is correct
General
✓✗Using anhydrous AlCl3 as catalyst, which one of the following reactions produces ethylbenzene?
- CH2=CH2 + C6H6
- CH3CH2OH + C6H6
- CH3CH3 + C6H6
- CH3CH=CH2 + C6H6
General
✓✗Nitration of toluene gives mainly
- benzoic acid
- m-nitrotoluene
- o- and p-nitrotoluene
- nitrobenzene and methane
General
✓✗The energy difference between the eclipsed and staggered conformations of ethane is about
- 348 kJ mol−1
- 12.5 kJ mol−1
- 1.25 kJ mol−1
- 125 kJ mol−1
General
✓✗Isomerisation of n-hexane by heating with anhydrous AlCl3 and HCl gives
- 2-methylpentane and 3-methylpentane
- benzene
- hex-1-ene
- cyclohexane
General
✓✗Vicinal dihalides on heating with zinc dust give
- alkenes
- alkynes
- alkanes
- alcohols
General
✓✗The major product of dehydrohalogenation of 2-bromobutane with alcoholic KOH is
- but-1-ene
- butane
- but-2-ene
- butan-2-ol