Motion in a plane - 07 Nov 2026
Question 1 of 15
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A ball is projected from the ground at angle θ. Its horizontal range is R and its maximum height is H. The angle of projection is
  • \( \tan^{-1}\left(\dfrac{H}{R}\right) \)
  • \( \tan^{-1}\left(\dfrac{2H}{R}\right) \)
  • \( \tan^{-1}\left(\dfrac{4H}{R}\right) \)
  • \( \tan^{-1}\left(\dfrac{R}{4H}\right) \)
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