General
✓✗The acceleration of a particle is increasing linearly with time t as bt The particle starts from origin with an initial velocity v0. The distance travelled by the particle in time t will be
-
v0t +
bt2
-
v0t +
bt2
-
v0t +
bt3
-
v0t +
bt3
General
✓✗A body dropped from a height h with initial velocity zero, strikes the ground with a velocity 3 m/s. Another body of same mass dropped from the same height h with an initial velocity of 4 m/s. The final velocity of second mass, with which it strikes the ground is
- 5 m/s
- 12 m/s
- 3 m/s
- 4 m/s
General
✓✗A car is moving along a straight road with a uniform acceleration. It passes through two points P and Q separated by a distance with velocity 30 km/h and 40 km/h respectively. The velocity of the car midway between P and Q is
- 33.3 km/h
-
km/h
-
km/h
- 35 km/h
General
✓✗The position x of a particle varies with time, (t) as x = at2 – bt3. The acceleration will be zero at time t is equal to
-
- zero
-
-
General
✓✗Two bodies A (of mass 1 kg) and B (of mass 3 kg) are dropped from heights of 16 m and 25 m, respectively. The ratio of the time taken by them to reach the ground is
- 4/5
- 5/4
- 12/5
- 5/12
General
✓✗A body dropped from top of a tower fall through 40 m during the last two seconds of its fall. The height of tower is (g = 10 m/s2)
- 60 m
- 45 m
- 80 m
- 50 m
General
✓✗Motion of a particle is given by equation s = (3t3 + 7t2 + 14t + 8) m. The value of acceleration of the particle at t = 1 sec is
- 10 m/s2
- 32 m/s2
- 23 m/s2
- 16 m/s2
General
✓✗A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is S1 and that covered in the first 20 seconds is S2, then
- S2 = 3S1
- S2 = 4S1
- S2 = S1
- S2 = 2S1
General
✓✗A car accelerates from rest at a constant rate a for some time after which it decelerates at a constant rate b and comes to rest. If total time elapsed is t, then maximum velocity acquired by car will be
General
✓✗A ball is thrown vertically upward. It has a speed of 10 m/sec when it has reached one half of its maximum height. How high does the ball rise? (Take g = 10 m/s2)
- 10 m
- 5 m
- 15 m
- 20 m
General
✓✗If the velocity of a particle is v = At + Bt2, where A and B are constants, then the distance travelled by it between 1 s and 2 s is
-
-
-
- 3A + 7B
General
✓✗The velocity of train increases uniformly from 20 km/h to 60 km/h in 4 hours. The distance travelled by the train during this period is
- 160 km
- 180 km
- 100 km
- 120 km
General
✓✗The water drop falls at regular intervals from a tap 5 m above the ground. The third drop is leaving the tap at instant the first drop touches the ground. How far above the ground is the second drop at that instant?
- 3.75 m
- 4.00 m
- 1.25 m
- 2.50 m
General
✓✗If a ball is thrown vertically upwards with speed u, the distance covered during the last t seconds of its ascent is
- ut
-
gt2
-
- (u + gt)t
General
✓✗A car moves a distance of 200 m. It covers the first half of the distance at speed 40 km/h and the second half of distance at speed v. The average speed is 48 km/h. The value of v is
- 56 km/h
- 60 km/h
- 50 km/h
- 48 km/h