General
✓✗Two balls are thrown simultaneously, A vertically upwards with 20 m/s and B vertically downwards with 20 m/s, from the same point high above the ground. Their separation after 2 s is
- 80 m
- 20 m
- 0
- 40 m
General
✓✗A body moving along a straight line has a velocity-time graph that is a horizontal line below the time axis. The body has
- constant negative acceleration
- increasing speed
- zero velocity
- constant negative velocity and zero acceleration
General
✓✗A ball is thrown vertically upwards with a velocity of 40 m/s. Its displacement after 5 s is (take g = 10 m s−2)
- 80 m above
- 75 m above the point of projection
- 125 m above
- 75 m below
General
✓✗Two bodies A (of mass 1 kg) and B (of mass 3 kg) are dropped from heights of 16 m and 25 m respectively. The ratio of the times taken by them to reach the ground is
- \( \dfrac{12}{5} \)
- \( \dfrac{5}{4} \)
- \( \dfrac{4}{5} \)
- \( \dfrac{5}{12} \)
General
✓✗Two cars start from rest at the same point with uniform accelerations of 2 m s−2 and 3 m s−2 along the same straight road. Their separation after 10 s is
- 100 m
- 25 m
- 50 m
- 500 m
General
✓✗From the top of a tower, a ball thrown vertically upwards with speed u takes time t1 to reach the ground, and a ball thrown vertically downwards with the same speed takes t2. A ball dropped from rest from the same point takes time
- \( \dfrac{2t_1t_2}{t_1 + t_2} \)
- \( \dfrac{t_1 - t_2}{2} \)
- \( \dfrac{t_1 + t_2}{2} \)
- \( \sqrt{t_1t_2} \)
General
✓✗Statement I: Displacement of a body can be zero even when the distance covered is not zero.
Statement II: Distance covered by a moving body can be zero.
Choose the correct answer.
Statement II: Distance covered by a moving body can be zero.
Choose the correct answer.
- Both Statement I and Statement II are correct
- Both Statement I and Statement II are incorrect
- Statement I is correct but Statement II is incorrect
- Statement I is incorrect but Statement II is correct
General
✓✗A train accelerates uniformly from rest at 2 m s−2 and then decelerates uniformly at 4 m s−2 to come to rest. If the total time of travel is 30 s, the maximum speed attained is
- 20 m/s
- 40 m/s
- 80 m/s
- 60 m/s
General
✓✗The position of a particle is \( x = 5t^2 \) (x in m, t in s). Its velocity at t = 2 s is
- 5 m/s
- 40 m/s
- 20 m/s
- 10 m/s
General
✓✗For the motion \( x = 3t^2 + 7t - 9 \) m, the instantaneous velocity equals the average velocity over the interval t = 1 s to t = 3 s at
- t = 1.5 s
- t = 2 s
- t = 3 s
- t = 2.5 s
General
✓✗A particle moving with uniform velocity has
- increasing acceleration
- constant non-zero acceleration
- zero acceleration
- negative acceleration
General
✓✗A particle starts from rest with uniform acceleration a. Match List I with List II.
| List I | List II |
| (a) Velocity after time t | (i) \( \tfrac12 at^2 \) |
| (b) Distance in time t | (ii) \( \tfrac{a}{2}(2t-1) \) |
| (c) Distance in the tth second | (iii) at |
| (d) Average velocity over time t | (iv) \( \tfrac12 at \) |
- (a)-(iii), (b)-(i), (c)-(ii), (d)-(iv)
- (a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)
- (a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)
- (a)-(iii), (b)-(ii), (c)-(i), (d)-(iv)
General
✓✗The acceleration of a particle is \( a = 6t \) m s−2. If it starts from rest at the origin, its displacement after 2 s is
- 4 m
- 24 m
- 8 m
- 12 m
General
✓✗A particle has retardation \( a = -k\sqrt{v} \). With initial velocity v0, the distance it covers before stopping is
- \( \dfrac{v_0^{3/2}}{k} \)
- \( \dfrac{2v_0^2}{3k} \)
- \( \dfrac{v_0^{1/2}}{2k} \)
- \( \dfrac{2v_0^{3/2}}{3k} \)
General
✓✗A bus is moving with a speed of 10 m s−1 on a straight road. A scooterist wishes to overtake the bus in 100 s. If the bus is at a distance of 1 km from the scooterist, with what speed should the scooterist chase the bus?
- 25 m s−1
- 40 m s−1
- 10 m s−1
- 20 m s−1